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	<title>Komente te: Fuqi te njepasnjeshme</title>
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	<link>http://blogumatematik.wordpress.com/2007/11/21/fuqi-te-njepasnjeshme/</link>
	<description>Mathematics is one of the essential emanations of the human spirit, a thing to be valued in and for itself, like art or poetry.</description>
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		<title>Sipas: valmir</title>
		<link>http://blogumatematik.wordpress.com/2007/11/21/fuqi-te-njepasnjeshme/#comment-102</link>
		<dc:creator>valmir</dc:creator>
		<pubDate>Mon, 12 May 2008 11:07:08 +0000</pubDate>
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		<description>zgjidhe  ket x^5-13y=8 dhe y^5-13x=-8</description>
		<content:encoded><![CDATA[<p>zgjidhe  ket x^5-13y=8 dhe y^5-13x=-8</p>
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		<title>Sipas: Ilirjan</title>
		<link>http://blogumatematik.wordpress.com/2007/11/21/fuqi-te-njepasnjeshme/#comment-28</link>
		<dc:creator>Ilirjan</dc:creator>
		<pubDate>Fri, 30 Nov 2007 15:26:15 +0000</pubDate>
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		<description>Ajo rruga e zgjidhjes nuk eshte dhe aq interesante, per mua, aq me teper qe i kam harruar ato formulat ez gjidhjeve per nje ekuacion te grades se katert. Por ne qofte se mund te me ndihmosh si ta zgjidh ne kete menyre: a^2 +b^2 + c^2 =0 and a+b+c = 3- w, ku a=x(x-1); b=y(y-1); c=z(z-1) and w=x+y+z. A ka mundesi te zgjidhet ky problem duke perdorur metoda te analizes komplekse apo ndonje metode tjeter?</description>
		<content:encoded><![CDATA[<p>Ajo rruga e zgjidhjes nuk eshte dhe aq interesante, per mua, aq me teper qe i kam harruar ato formulat ez gjidhjeve per nje ekuacion te grades se katert. Por ne qofte se mund te me ndihmosh si ta zgjidh ne kete menyre: a^2 +b^2 + c^2 =0 and a+b+c = 3- w, ku a=x(x-1); b=y(y-1); c=z(z-1) and w=x+y+z. A ka mundesi te zgjidhet ky problem duke perdorur metoda te analizes komplekse apo ndonje metode tjeter?</p>
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		<title>Sipas: blogumatematik</title>
		<link>http://blogumatematik.wordpress.com/2007/11/21/fuqi-te-njepasnjeshme/#comment-26</link>
		<dc:creator>blogumatematik</dc:creator>
		<pubDate>Fri, 30 Nov 2007 12:43:36 +0000</pubDate>
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		<description>Po ju jap rrugen e zgjidhjes
6*(x^4+y^4+z^4) = (x+y+z)^4 + 3*(x^2+y^2+z^2)^2 - 6*(x^2+y^2+z^2)(x+y+z)^2 + 8*(x^3+y^3+z^3)(x+y+z)
ky eshte ekuacioni zgjidhes.
Tani ne qofte se shenoni x+y+z=W duke zgjidhur kete ekuacion gjeni zgjidhjen.</description>
		<content:encoded><![CDATA[<p>Po ju jap rrugen e zgjidhjes<br />
6*(x^4+y^4+z^4) = (x+y+z)^4 + 3*(x^2+y^2+z^2)^2 &#8211; 6*(x^2+y^2+z^2)(x+y+z)^2 + 8*(x^3+y^3+z^3)(x+y+z)<br />
ky eshte ekuacioni zgjidhes.<br />
Tani ne qofte se shenoni x+y+z=W duke zgjidhur kete ekuacion gjeni zgjidhjen.</p>
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		<title>Sipas: blogumatematik</title>
		<link>http://blogumatematik.wordpress.com/2007/11/21/fuqi-te-njepasnjeshme/#comment-25</link>
		<dc:creator>blogumatematik</dc:creator>
		<pubDate>Fri, 30 Nov 2007 12:42:02 +0000</pubDate>
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		<description>Jo x+y+z=3 nuk eshte e sakte. Megjithate problemi nuk ka zgjidhje reale. Po ka zgjidhje komplekse.</description>
		<content:encoded><![CDATA[<p>Jo x+y+z=3 nuk eshte e sakte. Megjithate problemi nuk ka zgjidhje reale. Po ka zgjidhje komplekse.</p>
]]></content:encoded>
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		<title>Sipas: Ilirjan</title>
		<link>http://blogumatematik.wordpress.com/2007/11/21/fuqi-te-njepasnjeshme/#comment-20</link>
		<dc:creator>Ilirjan</dc:creator>
		<pubDate>Thu, 29 Nov 2007 20:32:45 +0000</pubDate>
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		<description>Anyway, I would say x+y+z=3. Eshte e sakte?</description>
		<content:encoded><![CDATA[<p>Anyway, I would say x+y+z=3. Eshte e sakte?</p>
]]></content:encoded>
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		<title>Sipas: Ilirjan</title>
		<link>http://blogumatematik.wordpress.com/2007/11/21/fuqi-te-njepasnjeshme/#comment-19</link>
		<dc:creator>Ilirjan</dc:creator>
		<pubDate>Thu, 29 Nov 2007 20:30:20 +0000</pubDate>
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		<description>Sistemi nuk ka zgjidhje reale; nenkuptohet qe mund te kete zgjidhje complexe?</description>
		<content:encoded><![CDATA[<p>Sistemi nuk ka zgjidhje reale; nenkuptohet qe mund te kete zgjidhje complexe?</p>
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